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A371303 Numbers k > 4 such that both k - 2^(2^m) and k + 2^(2^m) are prime for every natural m > 0 with 2^(2^m) < k. 0

%I #11 Mar 19 2024 12:42:03

%S 7,9,15,27,57,63,195,267,363,405,483,603,1197,1233,1443,1737,2715,

%T 4257,5403,6117,21855,22287,26817,40755,63777,260007,617253,986733,

%U 1151655,1167837,1174503,1199373,1331595,3233307,4128873,4138707,4609527,5938107,7203945,7605213,8379405,8587545,9596223

%N Numbers k > 4 such that both k - 2^(2^m) and k + 2^(2^m) are prime for every natural m > 0 with 2^(2^m) < k.

%C It seems that there are infinitely many such numbers.

%C If k > 7 is such a number, then it is odd and divisible by 3.

%C Conjecture: numbers k > 2 such that both k - 2^(2^m) and k + 2^(2^m) are prime for every integer m >= 0 with 2^(2^m) < k are only 9, 15, and 195 (_Amiram Eldar_ checked that there are no more terms k < 10^8).

%t q[k_] := Module[{m = 1}, While[2^(2^m) < k && PrimeQ[k - 2^(2^m)] && PrimeQ[k + 2^(2^m)], m++]; 2^(2^m) > k]; Select[Range[5, 10^6, 2], q] (* _Amiram Eldar_, Mar 18 2024 *)

%Y Cf. A039669, A129613, A370523.

%K nonn

%O 1,1

%A _Thomas Ordowski_, Mar 18 2024

%E More terms from _Amiram Eldar_, Mar 18 2024

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Last modified July 6 23:04 EDT 2024. Contains 374060 sequences. (Running on oeis4.)