OFFSET
3,2
COMMENTS
The (2, 3)-Lah numbers T(n, k) count ordered 2-tuples (pi(1), pi(2)) of partitions of the set {1, ..., n} into k linearly ordered blocks (lists, for short) such that the numbers 1, 2, 3 are in distinct lists, and bl(pi(1)) = bl(pi(2)) where for i = {1, 2} and pi(i) = b(1)^i, b(2)^i, ..., b(k)^i, where b(1)^i, b(2)^i, ..., b(k)^i are the blocks of partition pi(i), bl(pi(i)) = {min(b(1))^i, min(b(2))^i, ..., min(b(k))^i} is the set of block leaders, i.e., of minima of the lists in partition pi(i).
The (2, 3)-Lah numbers T(n, k) are the (m, r)-Lah numbers for m=2 and r=3. More generally, the (m, r)-Lah numbers count ordered m-tuples (pi(1), pi(2), ..., pi(m)) of partitions of the set {1, 2, ..., n} into k linearly ordered blocks (lists, for short) such that the numbers 1, 2, ..., r are in distinct lists, and bl(pi(1)) = bl(pi(2)) = ... = bl(pi(m)) where for i = {1, 2, ..., m} and pi(i) = {b(1)^i, b(2)^i, ..., b(k)^i}, where b(1)^i, b(2)^i,..., b(k)^i are the blocks of partition pi(i), bl(pi(i)) = {min(b(1))^i, min(b(2))^i, ..., min (b(k))^i} is the set of block leaders, i.e., of minima of the lists in partition pi(i).
LINKS
A. Žigon Tankosič, The (l, r)-Lah Numbers, Journal of Integer Sequences, Article 23.2.6, vol. 26 (2023).
FORMULA
Recurrence relation: T(n, k) = T(n-1, k-1) + (n+k-1)^2*T(n-1, k).
Explicit formula: T(n, k) = Sum_{4 <= j(1) < j(2) < ... < j(n-k) <= n} (2j(1)-2)^2 * (2j(2)-3)^2 * ... * (2j(n-k)-(n-k+1))^2.
Special cases:
T(n, k) = 0 for n < k or k < 3, [corrected by Paolo Xausa, Jun 11 2024]
T(n, n) = 1,
T(n, 3) = (A143498(n, 3))^2 = ((n+2)!)^2/14400,
T(n, n-1) = 2^2 * Sum_{j=3..n-1} j^2.
EXAMPLE
Triangle begins:
1;
36, 1;
1764, 100, 1;
112896, 9864, 200, 1;
9144576, 1099296, 34064, 344, 1;
914457600, 142159392, 6004512, 92200, 540, 1;
110649369600, 21385410048, 1156921920, 24075712, 213700, 796, 1.
...
An example for T(4, 3). The corresponding partitions are
pi(1) = {(1),(2),(3,4)},
pi(2) = {(1),(2),(4,3)},
pi(3) = {(1),(3),(2,4)},
pi(4) = {(1),(3),(4,2)},
pi(5) = {(1,4),(2),(3)},
pi(6) = {(4,1),(2),(3)}, since A143498 for n=4, k=3 equals 6. Sets of their block leaders are bl(pi(1)) = bl(pi(2)) = bl(pi(3)) = bl(pi(4)) = bl(pi(5)) = bl(pi(6)) = {1,2,3}.
Compute the number of ordered 2-tuples (i.e., ordered pairs) of partitions pi(1), pi(2), ..., pi(6) such that partitions in the same pair share the same set of block leaders. As there are six partitions with the set of block leaders equal to {1,2,3}, T(4, 3) = 6^2 = 36.
MAPLE
T:= proc(n, k) option remember; `if`(k<3 or k>n, 0,
`if`(n=k, 1, T(n-1, k-1)+(n+k-1)^2*T(n-1, k)))
end:
seq(seq(T(n, k), k=3..n), n=3..10);
MATHEMATICA
PROG
(Python)
def T_Lah(n, k):
if k < 3 or k > n:
return 0
elif n == k == 3:
return 1
else:
return T_Lah(n-1, k-1) + ((n+k-1)**2) * T_Lah(n-1, k)
def print_triangle(rows):
for n in range(rows):
row_values = [T_Lah(n, k) for k in range(n+1)]
print(' '.join(map(str, row_values)).center(rows*10))
rows = 10
print_triangle(rows)
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
Aleks Zigon Tankosic, Mar 16 2024
STATUS
approved