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A370528
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Number of permutations of [n] having exactly two adjacent 3-cycles.
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5
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0, 0, 0, 0, 0, 0, 1, 3, 12, 57, 348, 2460, 19806, 178950, 1794420, 19778210, 237696420, 3093642300, 43350548655, 650733622665, 10417925247240, 177191430300339, 3190747212651432, 60645032890871688, 1213255040678034508, 25484737348664027532, 560785511736390349080
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OFFSET
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0,8
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LINKS
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FORMULA
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G.f.: (1/2) * Sum_{k>=2} k! * x^(k+4) / (1+x^3)^(k+1).
a(n) = (1/2) * Sum_{k=0..floor(n/3)-2} (-1)^k * (n-2*k-4)! / k!.
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MATHEMATICA
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Table[Sum[(-1)^k*(n-2*k-4)!/k!, {k, 0, Floor[(n-6)/3]}]/2, {n, 0, 30}] (* G. C. Greubel, May 01 2024 *)
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PROG
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(PARI) my(N=30, x='x+O('x^N)); concat([0, 0, 0, 0, 0, 0], Vec(sum(k=2, N, k!*x^(k+4)/(1+x^3)^(k+1))/2))
(PARI) a(n, k=2, q=3) = sum(j=0, n\q-k, (-1)^j*(n-(q-1)*(j+k))!/j!)/k!;
(Magma)
[n le 5 select 0 else (&+[(-1)^k*Factorial(n-2*k-4)/Factorial(k): k in [0..Floor((n-6)/3)]])/2: n in [0..30]]; // G. C. Greubel, May 01 2024
(SageMath)
[sum((-1)^k*factorial(n-2*k-4)/factorial(k) for k in range(1+(n-6)//3))/2 for n in range(31)] # G. C. Greubel, May 01 2024
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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