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A369348
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a(1) = 1; for n > 1, a(n) is the smallest positive number such that a(n) - a(n-1) = sopfr(a(n)) + sopfr(a(n-1)), where sopfr(k) is the sum of the primes dividing k, with repetition.
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15
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1, 6, 20, 40, 106, 326, 568, 1294, 2071, 2323, 2603, 2867, 4467
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OFFSET
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1,2
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COMMENTS
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The sequence has only 12 terms beyond a(1) = 1 as there is no number k such that k - 4467 = sopfr(k) + sopfr(4467). See A369349 for the number of terms beyond each starting value n.
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LINKS
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MAPLE
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a(3) = 20 as a(2) = 6 and sopfr(20) + sopfr(6) = 9 + 5 = 14, which equals 20 - 6.
a(13) = 4467 as a(12) = 2867 and sopfr(4467) + sopfr(2867) = 1492 + 108 = 1600, which equals 4467 - 2867.
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CROSSREFS
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KEYWORD
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nonn,fini,full
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AUTHOR
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STATUS
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approved
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