OFFSET
0,2
COMMENTS
In general, for m>1, Sum_{k>=0} binomial(1/m,k)^2 = Gamma(1 + 2/m) / Gamma(1 + 1/m)^2.
FORMULA
a(n) ~ 4 * Pi * 3^(3*n + 1/2) / Gamma(1/3)^3.
MATHEMATICA
Table[27^n*Sum[Binomial[1/3, k]^2, {k, 0, n}], {n, 0, 16}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Vaclav Kotesovec, Nov 14 2023
STATUS
approved