OFFSET
0,2
FORMULA
a(n) = (1/(n+1)) * Sum_{k=0..floor(n/2)} binomial(n+1,k) * binomial(4*n-k+2,n-2*k).
From Seiichi Manyama, Oct 08 2025: (Start)
a(n) = (1/(n+1)) * Sum_{k=0..n} binomial(n+1,k) * binomial(3*n+k+1,n-k).
a(n) = (1/(n+1)) * [x^n] ((1-x+x^2) / (1-x)^4)^(n+1). (End)
PROG
(PARI) a(n) = sum(k=0, n\2, binomial(n+1, k)*binomial(4*n-k+2, n-2*k))/(n+1);
CROSSREFS
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Sep 27 2023
STATUS
approved
