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%I #12 Aug 05 2023 21:34:53
%S 21871365,37055184,37227993,39272583,41205603,43067463,44012682,
%T 44126949,47761635,48806274,49362234,49613484,50582103,52953795,
%U 54244068,60529077,60988653,61042069,62319465,63850344,66068793,66709683,66710004,67874079,67974312,68294148,68529900
%N The first term in a run of at least 4 consecutive numbers each with exactly 5 distinct prime factors (i.e. belong to A051270).
%e 21871365 is in the sequence as it starts a run of at least 4 consecutive numbers each with exactly 5 distinct prime factors.
%e That is each of 21871365 = 3 * 5 * 29 * 137 * 367, 21871365 + 1 = 21871366 = 2 * 11 * 37 * 97 * 277, 21871365 + 2 = 21871367 = 7*17*23*61*131, 21871365 + 3 = 21871368 = 2^3 * 3^2 * 31 * 41 * 239 have 5 distinct prime factors.
%o (PARI) upto(n) = {my(res = List(), streak = 0); n+=3; forfactored(i = 1, n, if(omega(i[2]) == 5, streak++; if(streak >= 4, listput(res, i[1]-3)), streak = 0)); res}
%Y Cf. A051270, A364266.
%K nonn
%O 1,1
%A _David A. Corneth_, Jul 24 2023
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