login
Parity of Dirichlet inverse of A075255, where A075255(n) = n - sopfr(n), where sopfr is the sum of prime factors (with repetition).
3

%I #11 Jan 17 2023 10:01:14

%S 1,0,0,0,0,1,0,0,1,1,0,1,0,1,1,0,0,0,0,1,1,1,0,1,1,1,0,1,0,0,0,0,1,1,

%T 1,1,0,1,1,1,0,0,0,1,0,1,0,1,1,0,1,1,0,1,1,1,1,1,0,0,0,1,0,0,1,0,0,1,

%U 1,0,0,0,0,1,0,1,1,0,0,1,0,1,0,0,1,1,1,1,0,1,1,1,1,1,1,1,0,0,0,1,0,0,0,1,0,1,0,1,0,0,1,1,0,0,1,1,0,1,1,0,1

%N Parity of Dirichlet inverse of A075255, where A075255(n) = n - sopfr(n), where sopfr is the sum of prime factors (with repetition).

%C Note that here a(n) = 1 does not imply that A359768(n) = 1 also. The difference A359768(n) - a(n) can be -1, 0, or +1. This in contrast to sequences like A359774. See also A359816.

%H Antti Karttunen, <a href="/A359787/b359787.txt">Table of n, a(n) for n = 1..100000</a>

%H <a href="/index/Ch#char_fns">Index entries for characteristic functions</a>

%F a(n) = A359788(n) mod 2.

%o (PARI) A359787(n) = (A359788(n)%2);

%Y Cf. A001414, A075255, A359768, A359774, A359788.

%Y Cf. also A359764 [= a(A003961(n))], A359816.

%K nonn

%O 1

%A _Antti Karttunen_, Jan 16 2023