%I #16 Aug 16 2023 02:27:13
%S 0,1,0,1,1,1,0,2,0,1,1,2,0,2,0,1,1,1,1,3,0,1,1,1,0,3,0,2,1,1,0,3,1,1,
%T 1,2,0,2,0,2,1,1,0,4,1,1,2,1,0,2,0,2,1,2,0,3,0,2,1,2,1,3,0,1,1,1,0,5,
%U 0,1,2,1,0,2,1,2,1,1,1,4,0,2,1,3,0,2,0,1,2,1
%N Number of divisors of 5*n-4 of form 5*k+2.
%C Also number of divisors of 5*n-4 of form 5*k+3.
%H Seiichi Manyama, <a href="/A359244/b359244.txt">Table of n, a(n) for n = 1..10000</a>
%F a(n) = A001877(5*n-4) = A001878(5*n-4).
%F G.f.: Sum_{k>0} x^(2*k)/(1 - x^(5*k-2)).
%F G.f.: Sum_{k>0} x^(3*k-1)/(1 - x^(5*k-3)).
%t a[n_] := DivisorSum[5*n-4, 1 &, Mod[#, 5] == 2 &]; Array[a, 100] (* _Amiram Eldar_, Aug 16 2023 *)
%o (PARI) a(n) = sumdiv(5*n-4, d, d%5==2);
%o (PARI) a(n) = sumdiv(5*n-4, d, d%5==3);
%o (PARI) my(N=100, x='x+O('x^N)); concat(0, Vec(sum(k=1, N, x^(2*k)/(1-x^(5*k-2)))))
%o (PARI) my(N=100, x='x+O('x^N)); concat(0, Vec(sum(k=1, N, x^(3*k-1)/(1-x^(5*k-3)))))
%Y Cf. A001877, A001878.
%K nonn,easy
%O 1,8
%A _Seiichi Manyama_, Dec 22 2022