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%I #18 Jan 05 2024 12:29:43
%S 1,1,0,1,1,0,1,0,2,0,1,0,2,5,0,1,0,0,6,15,0,1,0,0,6,26,52,0,1,0,0,0,
%T 36,150,203,0,1,0,0,0,24,150,962,877,0,1,0,0,0,0,240,900,6846,4140,0,
%U 1,0,0,0,0,120,1560,9366,54266,21147,0,1,0,0,0,0,0,1800,8400,101556,471750,115975,0
%N Square array T(n,k), n >= 0, k >= 0, read by antidiagonals downwards, where T(n,k) = Sum_{j=0..n} (k*j)!* Stirling2(n,k*j)/j!.
%H Andrew Howroyd, <a href="/A357869/b357869.txt">Table of n, a(n) for n = 0..1325</a> (first 51 antidiagonals)
%F For k > 0, e.g.f. of column k: exp((exp(x) - 1)^k).
%F T(0,k) = 1; T(n,k) = k! * Sum_{j=1..n} binomial(n-1,j-1) * Stirling2(j,k) * T(n-j,k).
%e Square array begins:
%e 1, 1, 1, 1, 1, 1, ...
%e 0, 1, 0, 0, 0, 0, ...
%e 0, 2, 2, 0, 0, 0, ...
%e 0, 5, 6, 6, 0, 0, ...
%e 0, 15, 26, 36, 24, 0, ...
%e 0, 52, 150, 150, 240, 120, ...
%o (PARI) T(n, k) = sum(j=0, n, (k*j)!*stirling(n, k*j, 2)/j!);
%o (PARI) T(n, k) = if(k==0, 0^n, n!*polcoef(exp((exp(x+x*O(x^n))-1)^k), n));
%Y Columns k=0-4 give: A000007, A000110, A052859, A353664, A353665.
%Y Cf. A324162, A357293, A357868.
%K nonn,tabl
%O 0,9
%A _Seiichi Manyama_, Oct 17 2022