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%I #8 Nov 04 2022 11:26:32
%S 1,0,1,1,1,1,0,1,0,0,1,1,1,1,0,0,1,1,1,1,0,0,1,1,1,0,0,0,1,1,1,1,1,0,
%T 1,0,0,1,0,0,1,1,1,1,0,0,0,1,0,0,0,0,0,1,1,0,1,0,1,1,1,1,0,0,0,0,1,1,
%U 0,0,1,1,1,1,0,0,0,0,1,1,1,0,1,1,1,0,0,0,0,1,1,0,0,0,0,0,1,1,0,0,0,1,0,1,1,1,0,1,1,1,0,0,0,1,1,0,0,0,1,0,1
%N a(n) = 1 if A003415(n) and A276086(n) are relatively prime, otherwise 0. Here A003415 is the arithmetic derivative, and A276086 is the primorial base exp-function.
%H Antti Karttunen, <a href="/A356310/b356310.txt">Table of n, a(n) for n = 0..100000</a>
%H <a href="/index/Ch#char_fns">Index entries for characteristic functions</a>
%H <a href="/index/Pri#primorialbase">Index entries for sequences related to primorial base</a>
%F a(n) = [1 == A327858(n)], where [ ] is the Iverson bracket.
%o (PARI)
%o A003415(n) = if(n<=1, 0, my(f=factor(n)); n*sum(i=1, #f~, f[i, 2]/f[i, 1]));
%o A276086(n) = { my(m=1, p=2); while(n, m *= (p^(n%p)); n = n\p; p = nextprime(1+p)); (m); };
%o A356310(n) = (1==gcd(A003415(n),A276086(n)));
%Y Characteristic function of A356311, whose complement A356312 gives the positions of 0's.
%Y Cf. A003415, A276086, A327858.
%Y Cf. also A356162.
%K nonn
%O 0
%A _Antti Karttunen_, Nov 03 2022
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