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A355971
Numerator of the cross-ratio of the four primes p_n, p_{n+1}, p_{n+2}, p_{n+3}, where p_n = prime(n).
1
6, 3, 9, 9, 9, 9, 5, 10, 16, 10, 5, 9, 5, 5, 8, 16, 10, 5, 2, 10, 25, 35, 7, 9, 9, 9, 9, 27, 81, 15, 10, 8, 36, 8, 8, 5, 25, 5, 8, 8, 36, 9, 9, 7, 14, 8, 4, 9, 5, 10, 8, 16, 16, 4, 8, 16, 10, 5, 9, 72, 54, 27, 9, 27, 15, 16, 16, 9, 5, 35, 49, 7, 5, 25, 35, 7, 9, 27, 27, 36, 36, 8, 10, 25, 35, 7, 9, 9, 4, 10, 5, 9, 9
OFFSET
1,1
COMMENTS
Conjecture: all integers >= 2 occur at least once among the sequence of cross-ratios.
FORMULA
a(n) = numerator of ((p_n-p_(n+2))/(p_n-p_(n+3))) * ((p_(n+1)-p_(n+3))/(p_(n+1)-p_(n+2))) where p_n = prime(n) is the n-th prime.
EXAMPLE
Cross-ratio fractions begin 6/5, 3/2, 9/8, 9/5, 9/8, 9/5, 5/4, 10/9, 16/7, 10/9, ...
PROG
(PARI) a(n) = my(p=prime(n), p1=nextprime(p+1), p2=nextprime(p1+1), p3=nextprime(p2+1)); numerator((((p-p2)/(p-p3))*((p1-p3)/(p1-p2)))); \\ Michel Marcus, Jul 29 2022
CROSSREFS
Cf. A000040, A355972 (denominators).
Sequence in context: A176533 A214497 A177015 * A327000 A249948 A066070
KEYWORD
nonn,frac
AUTHOR
Samir Fridhi, Jul 21 2022
STATUS
approved