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A354876
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Sum of A344005 and its Dirichlet inverse, where A344005(n) is the smallest positive m such that n divides the oblong number m*(m+1).
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2
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2, 0, 0, 1, 0, 4, 0, 5, 4, 8, 0, 10, 0, 12, 16, 15, 0, 12, 0, 20, 24, 20, 0, 12, 16, 24, 24, 30, 0, -6, 0, 35, 40, 32, 48, 20, 0, 36, 48, 20, 0, -12, 0, 50, 36, 44, 0, 9, 36, 32, 64, 60, 0, 28, 80, 32, 72, 56, 0, -63, 0, 60, 48, 71, 96, -18, 0, 80, 88, -20, 0, 32, 0, 72, 40, 90, 120, -24, 0, 10, 88, 80, 0, -98, 128
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OFFSET
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1,1
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LINKS
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FORMULA
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a(1) = 2, and for n > 1, a(n) = -Sum_{d|n, 1<d<n} A344005(d) * A354875(n/d).
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PROG
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(PARI)
A344005(n) = for(m=1, oo, if((m*(m+1))%n==0, return(m))); \\ From A344005
memoA354875 = Map();
A354875(n) = if(1==n, 1, my(v); if(mapisdefined(memoA354875, n, &v), v, v = -sumdiv(n, d, if(d<n, A344005(n/d)*A354875(d), 0)); mapput(memoA354875, n, v); (v)));
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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STATUS
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approved
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