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A348511
Numbers k for which 2k+1 can be obtained with successive prime shifts towards larger primes (by iterating A003961, starting from k).
3
2, 3, 4, 5, 10, 11, 23, 29, 41, 53, 57, 83, 89, 113, 131, 173, 179, 191, 233, 239, 251, 281, 293, 359, 419, 431, 443, 491, 509, 593, 641, 653, 659, 683, 719, 743, 761, 809, 911, 953, 1013, 1019, 1031, 1049, 1054, 1103, 1223, 1229, 1289, 1409, 1439, 1451, 1481, 1499, 1511, 1559, 1583, 1601, 1733, 1811, 1889, 1901, 1931
OFFSET
1,1
COMMENTS
Numbers k for which A246277(2k+1) = A246277(k). This in turn implies a looser condition A046523(2k+1) = A046523(k).
Conjecture: Apart from 4 all other terms in this sequence are squarefree. No counterexamples <= 2^22.
EXAMPLE
4 is present, because by applying prime shift once to it, we get A003961(4) = 9 = 2*4 + 1.
5 is present, because by applying prime shift twice to it, we get 5 -> 7 -> 11 = 2*5 + 1.
MAPLE
filter:= proc(n) local F, F1, F2, G, G1, G2;
F:= sort(ifactors(n)[2], (a, b) -> a[1]<b[1]);
G:= sort(ifactors(2*n+1)[2], (a, b) -> a[1]<b[1]);
if nops(F) <> nops(G) then return false fi;
F2:= map(t -> t[2], F);
G2:= map(t -> t[2], G);
if F2 <> G2 then return false fi;
if nops(F) = 1 then return true fi;
F1:= map(t -> numtheory:-pi(t[1]), F);
G1:= map(t -> numtheory:-pi(t[1]), G);
nops(convert(G1-F1, set))=1;
end proc:
select(filter, [$2..10000]); # Robert Israel, Feb 18 2022
MATHEMATICA
f[p_, e_] := NextPrime[p]^e; s[1] = 1; s[n_] := Times @@ f @@@ FactorInteger[n]; q[n_] := NestWhileList[s, n, # < 2*n + 1 &][[-1]] == 2*n + 1; Select[Range[2, 2000], q] (* Amiram Eldar, Oct 30 2021 *)
PROG
(PARI)
A246277(n) = if(1==n, 0, my(f = factor(n), k = primepi(f[1, 1])-1); for (i=1, #f~, f[i, 1] = prime(primepi(f[i, 1])-k)); factorback(f)/2);
isA348511(n) = (A246277(n)==A246277(1+n+n));
CROSSREFS
Subsequences: A005384 (primes present), A348514 (terms requiring only one iteration to reach 2k+1).
Cf. also A285706.
Sequence in context: A348255 A117360 A074821 * A338897 A296160 A076707
KEYWORD
nonn
AUTHOR
Antti Karttunen, Oct 30 2021
STATUS
approved