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A347589
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Continued fraction for Sum_{k>=0} 1/2^(3^k).
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0
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0, 1, 1, 1, 2, 7, 1, 1, 1, 1, 1, 511, 2, 1, 1, 1, 7, 2, 1, 1, 1, 134217727, 2, 1, 2, 7, 1, 1, 1, 2, 511, 1, 1, 1, 1, 1, 7, 2, 1, 1, 1, 2417851639229258349412351, 2, 1, 2, 7, 1, 1, 1, 1, 1, 511, 2, 1, 1, 1, 7, 2, 1, 2, 134217727, 1, 1, 1, 2, 7, 1, 1, 1, 2, 511, 1, 1, 1, 1, 1, 7, 2, 1, 1, 1
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OFFSET
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0,5
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LINKS
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FORMULA
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a(5*2^k+2) = 2^(3^(k+1)) - 1. Other terms are obtained by symmetry around (5*2^k,5*2^k+1,5*2^k+2,5*2^k+3). For instance 1, 1, 1, 2, 7, 1, 1, 1, (1, 1, 511, 2), 1, 1, 1, 7, 2, 1, 1, 1.
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MATHEMATICA
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ContinuedFraction[N[Sum[1/2^(3^k), {k, 0, Infinity}], 250]] (* Stefano Spezia, Sep 11 2021 *)
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PROG
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(PARI) contfrac(suminf(k=0, 1/2^(3^k))) \\ Michel Marcus, Sep 11 2021
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CROSSREFS
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KEYWORD
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nonn,cofr
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AUTHOR
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STATUS
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approved
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