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a(n) = A346422(4*A003754(n-1) + 3) for n > 1 with a(1) = 1.
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%I #18 Apr 21 2024 22:12:32

%S 1,2,6,4,24,18,12,120,8,96,72,48,720,54,36,600,24,480,360,240,5040,16,

%T 384,288,192,4320,216,144,3600,96,2880,2160,1440,40320,162,108,3000,

%U 72,2400,1800,1200,35280,48,1920,1440,960,30240,1080,720,25200,480,20160

%N a(n) = A346422(4*A003754(n-1) + 3) for n > 1 with a(1) = 1.

%C To get the distinct terms of A346422 in the order of their appearance up to A346422(2^n - 1), just take the first A000045(n+1) terms of this sequence and remove the duplicates.

%F a(n) = (1 + A200649(n))*a(n - A130312(n-1)) for n > 1 with a(1) = 1.

%F a(n) = A346422(4*A003754(n-1) + 3) for n > 1 with a(1) = 1.

%Y Cf. A003754, A130312, A200649, A346422.

%K nonn

%O 1,2

%A _Mikhail Kurkov_, Aug 21 2021 [verification needed]