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%I #20 Jul 31 2021 19:55:14
%S 1,6,9,3,9,4,9,1,3,7,8,3,8,0,0,0,4,0,8,2,5,3,0,7,6,9,5,2,1,7,0,7,2,1,
%T 9,3,4,8,7,6,5,7,8,2,6,7,5,3,4,4,9,1,1,1,5,9,4,7,9,5,0,3,6,2,4,0,8,2,
%U 7,1,8,6,5,9,9,7,5,9,5,0,6,7,1,7,0,6,5,4,2,8,8,9,2,4,6,1,1,7,2,1
%N Decimal expansion of A205083 read as a binary fraction.
%C This constant can be used to calculate the index n of A061419(k) in A344792: n = floor(1.6939... * 2^(k-1)) for k>0.
%C Likewise, since A345671 is the inverse of A344792, A345671(A061419(n)) = floor(1.6939... * 2^(n-1)).
%F Equals Sum_{n>=1} A205083(n)/2^(n-1).
%F Equals lim_{n -> infinity} (A345671(A061419(n))/2^(n-1)).
%e 1.693949137838000408253076952170721934876578267534491115947...
%Y Cf. A205083, A344792, A345671.
%K nonn,cons
%O 1,2
%A _John-Vincent Saddic_, Jul 08 2021