login
The OEIS is supported by the many generous donors to the OEIS Foundation.

 

Logo
Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A345623 Numbers that are the sum of nine fifth powers in six or more ways. 7
926404, 936607, 952896, 985421, 993574, 993605, 993816, 1075779, 1123321, 1133344, 1134367, 1151406, 1160105, 1166111, 1177144, 1206514, 1209669, 1209847, 1215545, 1225630, 1251130, 1264929, 1265320, 1278611, 1414834, 1422367, 1422609, 1430384, 1431367 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
LINKS
EXAMPLE
936607 is a term because 936607 = 1^5 + 1^5 + 2^5 + 7^5 + 10^5 + 11^5 + 11^5 + 12^5 + 12^5 = 1^5 + 3^5 + 4^5 + 7^5 + 7^5 + 8^5 + 12^5 + 12^5 + 13^5 = 1^5 + 3^5 + 5^5 + 6^5 + 8^5 + 8^5 + 11^5 + 11^5 + 14^5 = 2^5 + 4^5 + 4^5 + 6^5 + 6^5 + 9^5 + 11^5 + 11^5 + 14^5 = 2^5 + 5^5 + 5^5 + 5^5 + 6^5 + 8^5 + 10^5 + 12^5 + 14^5 = 4^5 + 4^5 + 4^5 + 7^5 + 8^5 + 8^5 + 8^5 + 9^5 + 15^5.
PROG
(Python)
from itertools import combinations_with_replacement as cwr
from collections import defaultdict
keep = defaultdict(lambda: 0)
power_terms = [x**5 for x in range(1, 1000)]
for pos in cwr(power_terms, 9):
tot = sum(pos)
keep[tot] += 1
rets = sorted([k for k, v in keep.items() if v >= 6])
for x in range(len(rets)):
print(rets[x])
CROSSREFS
Sequence in context: A105011 A345613 A346330 * A346341 A115172 A186557
KEYWORD
nonn
AUTHOR
STATUS
approved

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recents
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified February 29 09:21 EST 2024. Contains 370418 sequences. (Running on oeis4.)