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A345565 Numbers that are the sum of six fourth powers in eight or more ways. 8
58035, 59780, 87746, 88595, 96195, 96450, 102371, 106451, 106515, 108035, 108275, 108290, 108771, 112370, 112931, 115251, 122835, 122850, 122915, 124691, 125971, 132546, 133395, 133571, 133586, 134675, 134931, 136931, 138275, 138595, 143650, 144755, 144835 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

LINKS

Sean A. Irvine, Table of n, a(n) for n = 1..10000

EXAMPLE

59780 is a term because 59780 = 1^4 + 1^4 + 1^4 + 5^4 + 12^4 + 14^4 = 1^4 + 1^4 + 6^4 + 6^4 + 9^4 + 15^4 = 1^4 + 2^4 + 9^4 + 10^4 + 11^4 + 13^4 = 1^4 + 4^4 + 7^4 + 7^4 + 8^4 + 15^4 = 1^4 + 7^4 + 7^4 + 9^4 + 10^4 + 14^4 = 2^4 + 5^4 + 6^4 + 11^4 + 11^4 + 13^4 = 3^4 + 7^4 + 8^4 + 10^4 + 11^4 + 13^4 = 5^4 + 6^4 + 7^4 + 7^4 + 11^4 + 14^4.

PROG

(Python)

from itertools import combinations_with_replacement as cwr

from collections import defaultdict

keep = defaultdict(lambda: 0)

power_terms = [x**4 for x in range(1, 1000)]

for pos in cwr(power_terms, 6):

tot = sum(pos)

keep[tot] += 1

rets = sorted([k for k, v in keep.items() if v >= 8])

for x in range(len(rets)):

print(rets[x])

CROSSREFS

Cf. A344944, A345517, A345564, A345566, A345574, A345722, A345820.

Sequence in context: A119887 A188256 A124729 * A345820 A184372 A237402

Adjacent sequences: A345562 A345563 A345564 * A345566 A345567 A345568

KEYWORD

nonn

AUTHOR

David Consiglio, Jr., Jun 20 2021

STATUS

approved

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Last modified February 1 08:20 EST 2023. Contains 359992 sequences. (Running on oeis4.)