A345536 Numbers that are the sum of eight cubes in six or more ways.

628, 719, 769, 776, 778, 795, 832, 839, 846, 858, 860, 865, 872, 875, 876, 882, 886, 891, 893, 895, 901, 902, 907, 908, 912, 921, 927, 928, 931, 938, 945, 946, 947, 951, 954, 956, 958, 963, 964, 965, 970, 972, 977, 982, 984, 989, 991, 992, 996, 998, 999, 1001

Offset

1,1

Links

Sean A. Irvine, Table of n, a(n) for n = 1..10000

Example

719 is a term because 719 = 1^3 + 1^3 + 1^3 + 4^3 + 4^3 + 4^3 + 4^3 + 5^3 = 1^3 + 1^3 + 2^3 + 3^3 + 4^3 + 4^3 + 5^3 + 5^3 = 1^3 + 2^3 + 2^3 + 3^3 + 3^3 + 5^3 + 5^3 + 5^3 = 2^3 + 2^3 + 2^3 + 2^3 + 3^3 + 3^3 + 5^3 + 6^3 = 2^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 3^3 + 7^3 = 3^3 + 3^3 + 3^3 + 3^3 + 4^3 + 4^3 + 4^3 + 4^3.

Prog

(Python)
from itertools import combinations_with_replacement as cwr
from collections import defaultdict
keep = defaultdict(lambda: 0)
power_terms = [x**3 for x in range(1, 1000)]
for pos in cwr(power_terms, 8):
    tot = sum(pos)
    keep[tot] += 1
    rets = sorted([k for k, v in keep.items() if v >= 6])
    for x in range(len(rets)):
        print(rets[x])

Crossrefs

Cf. A345493, A345524, A345535, A345537, A345545, A345581, A345788.

Sequence in context: A188362 A098260 A224603 * A345788 A261708 A098261

Adjacent sequences: A345533 A345534 A345535 * A345537 A345538 A345539

Keyword

nonn

Author

David Consiglio, Jr., Jun 20 2021

Status

approved