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A345403
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Riesel problem in base 5: a(n) is the smallest k >= 0 such that (2*n)*5^k - 1 is prime, or -1 if no such k exists.
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1
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4, 0, 0, 0, 3, 0, 0, 1, 0, 0, 1, 0, 4, 1, 0, 0, 163, 1, 0, 1, 0, 0, 1, 0, 2, 5, 0, 2, 7, 0, 0, 5, 5, 0, 1, 0, 0, 1, 1, 0, 1, 0, 2058, 1, 0, 26, 5, 1, 0, 1, 0, 0, 3, 0, 0, 3, 0, 32, 17, 1, 2, 1, 3, 0, 3, 0, 8, 21, 0, 0, 1, 1, 4, 1, 0, 0, 1, 4, 0, 7, 1, 0, 1, 0
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OFFSET
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1,1
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COMMENTS
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a(346802/2) = a(173401) = -1 (see A273987).
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LINKS
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EXAMPLE
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For n = 5: 10*5^k - 1 is composite for k = 0, 1, 2 and prime for k = 3. Since 3 is the smallest such k, a(5) = 3.
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PROG
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(PARI) a(n) = for(k=0, oo, if(ispseudoprime((2*n)*5^k-1), return(k)))
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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STATUS
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approved
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