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A345175 Numbers that are the sum of five third powers in exactly six ways. 7
2430, 2979, 3214, 3249, 3312, 3492, 3520, 3737, 3753, 3788, 3816, 3842, 3942, 3968, 4121, 4185, 4213, 4267, 4355, 4411, 4418, 4446, 4453, 4456, 4465, 4482, 4509, 4563, 4626, 4663, 4670, 4723, 4753, 4896, 4905, 4924, 4938, 4941, 4950, 4960, 4976, 4987, 4994 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

Differs from A345174 at term 20 because 4392 = 1^3 + 1^3 + 10^3 + 10^3 + 11^3  = 1^3 + 2^3 + 2^3 + 9^3 + 14^3  = 1^3 + 8^3 + 9^3 + 10^3 + 10^3  = 2^3 + 2^3 + 3^3 + 5^3 + 15^3  = 2^3 + 3^3 + 5^3 + 8^3 + 14^3  = 2^3 + 8^3 + 8^3 + 8^3 + 12^3  = 3^3 + 6^3 + 7^3 + 8^3 + 13^3  = 5^3 + 5^3 + 5^3 + 9^3 + 13^3.

LINKS

David Consiglio, Jr., Table of n, a(n) for n = 1..10000

EXAMPLE

2430 is a term because 2430 = 1^3 + 2^3 + 2^3 + 5^3 + 12^3  = 1^3 + 3^3 + 4^3 + 7^3 + 11^3  = 2^3 + 2^3 + 6^3 + 6^3 + 11^3  = 2^3 + 3^3 + 3^3 + 9^3 + 10^3  = 3^3 + 5^3 + 8^3 + 8^3 + 8^3  = 3^3 + 4^3 + 7^3 + 8^3 + 9^3.

PROG

(Python)

from itertools import combinations_with_replacement as cwr

from collections import defaultdict

keep = defaultdict(lambda: 0)

power_terms = [x**3 for x in range(1, 1000)]

for pos in cwr(power_terms, 5):

    tot = sum(pos)

    keep[tot] += 1

rets = sorted([k for k, v in keep.items() if v == 6])

for x in range(len(rets)):

    print(rets[x])

CROSSREFS

Cf. A294740, A343988, A344941, A345149, A345174, A345181, A345768.

Sequence in context: A340899 A186874 A345174 * A202201 A147984 A229871

Adjacent sequences:  A345172 A345173 A345174 * A345176 A345177 A345178

KEYWORD

nonn

AUTHOR

David Consiglio, Jr., Jun 10 2021

STATUS

approved

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Last modified December 1 16:44 EST 2021. Contains 349430 sequences. (Running on oeis4.)