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 A344671 a(n) is the total number of stable matchings for all possible preference profiles in the stable marriage problem with n men and n women such that there exists a married couple where the woman and the man rank each other last. 1
 1, 4, 4608, 5317484544 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,2 COMMENTS A man and a woman who rank each other last and end up in a marriage are called a hell-couple. A stable matching cannot have more than one hell-couple. Given a profile, if there exists a stable matching with a hell-couple, then all the stable matchings for this profile have the same hell-couple. The Gale-Shapley algorithm (both men-proposing and women-proposing) for such a profile needs at least n rounds to terminate. A344670(n) is the number of preference profiles such that there exists a stable matching with a hell-couple. This sequence is distinct from A344670 because in this sequence profiles are counted with their respective multiplicity if they yield multiple stable matchings with a hell-couple. LINKS Table of n, a(n) for n=1..4. Matvey Borodin, Eric Chen, Aidan Duncan, Tanya Khovanova, Boyan Litchev, Jiahe Liu, Veronika Moroz, Matthew Qian, Rohith Raghavan, Garima Rastogi, and Michael Voigt, Sequences of the Stable Matching Problem, arXiv:2201.00645 [math.HO], 2021. Wikipedia, Gale-Shapley algorithm. EXAMPLE For n = 2, each preference profile that has a hell-couple has exactly one stable matching, thus a(2) = A344670(2) = 4. For n > 2, this is no longer the case and a(n) > A344670(n). CROSSREFS Cf. A185141, A344670. Sequence in context: A127235 A274972 A344670 * A203036 A306962 A102205 Adjacent sequences: A344668 A344669 A344670 * A344672 A344673 A344674 KEYWORD nonn,more AUTHOR Tanya Khovanova and MIT PRIMES STEP Senior group, Jun 05 2021 STATUS approved

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Last modified May 18 09:54 EDT 2024. Contains 372620 sequences. (Running on oeis4.)