OFFSET
1,1
COMMENTS
A concatenation of 10 and n provides the proof of existence and also an upper bound for a(n).
The bound is exact for n = 9, 90, 900, ...
LINKS
Rémy Sigrist, Table of n, a(n) for n = 1..8999
EXAMPLE
102 + 9*11 = 201 which is a permutation of digits of 102, and no smaller number has this feature, hence a(11)=102.
PROG
(PARI) a(n) = { for (v=1, oo, if (vecsort(digits(v))==vecsort(digits(v+9*n)), return (v))) } \\ Rémy Sigrist, May 03 2021
CROSSREFS
KEYWORD
AUTHOR
Ivan Neretin, May 02 2021
STATUS
approved