OFFSET
0,1
COMMENTS
log(cos(1/n)) ~ -1/(2*n^2) when n -> oo, so the series log(cos(1/n)) is convergent (A336603), but
log(sin(1/n)) ~ -log(n) when n -> oo, so the series log(sin(1/n)) is divergent.
However, as log(cos(1/n)) * log(sin(1/n)) ~ log(n)/(2*n^2) when n -> oo, the series log(cos(1/n)) * log(sin(1/n)) is convergent.
REFERENCES
Jean-Marie Monier, Analyse, Exercices corrigés, 2ème année MP, Dunod, 1997, Exercice 3.2.1.f p. 279.
FORMULA
Equals Sum_{n>=1} log(cos(1/n)) * log(sin(1/n)).
EXAMPLE
0.588251433968163564741783117942531437228475727762559...
PROG
(PARI) sumpos(n=1, log(cos(1/n)) * log(sin(1/n))) \\ Michel Marcus, Mar 18 2021
CROSSREFS
KEYWORD
AUTHOR
Bernard Schott, Mar 17 2021
EXTENSIONS
a(4)-a(51) from Jon E. Schoenfield, Mar 18 2021
STATUS
approved