A342443(1) = 5 = 2 + 3, hence a(1) = 2.
A342443(2) = 97 = 29 + 31 + 37, hence a(2) = 3.
a(n) =
sum of consecutive primes number of
----------------------------------------- consecutive
-- ----------------------------------------- -----------
1 2 + 3 = 5 2
2 29 + 31 + 37 = 97 3
3 191 + ... = 991 5
4 1087 + ... = 9949 9
5 19979 + ... = 99971 5
6 34337 + ... = 999983 29
7 34129 + ... = 9999991 281
8 54829 + ... = 99999989 1575
9 1665437 + ... = 999999937 599
10 1428571363 + ... = 9999999943 7
11 5882352691 + ... = 99999999977 17
12 333333333299 + ... = 999999999989 3
13 1550560001 + ... = 9999999999763 6449
14 13384757 + ... = 99999999999959 2725361
(End)
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