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A340230 a(n) is the smallest number m such that numbers m, m + 1, m + 2, ..., m + n - 1 have k, 2*k, 4*k, 8*k, ..., (2^(n-1))*k divisors respectively. 1
1, 1, 193, 613, 1124581, 52071301, 213536830501 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,3
COMMENTS
a(n) is the smallest number m such that tau(m) = tau(m + 1) / 2 = tau(m + 2) / 4 = tau(m + 3) / 8 = ... = tau(m + n - 1) / 2^(n - 1), where tau(k) = the number of divisors of k (A000005).
Conjecture: a(7) = 213536830501.
LINKS
EXAMPLE
a(4) = 613 because 613 is the smallest term of 4 consecutive numbers with this property: tau(613) = 2, tau(614) = 4, tau(615) = 8, tau(616) = 16.
PROG
(PARI) isok(m, n) = my(nb=numdiv(m)); for (k=1, n-1, if (numdiv(m+k)/nb != 2^k, return(0))); return (1);
a(n) = my(k=1); while (!isok(k, n), k++); k; \\ Michel Marcus, Jan 05 2021
CROSSREFS
Cf. A100366 (similar sequence for primes).
Sequence in context: A105129 A140631 A142117 * A142564 A174521 A374607
KEYWORD
nonn,more
AUTHOR
Jaroslav Krizek, Jan 01 2021
EXTENSIONS
a(7), as conjectured by Jaroslav Krizek, from Martin Ehrenstein, Feb 06 2021
STATUS
approved

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Last modified August 11 14:50 EDT 2024. Contains 375073 sequences. (Running on oeis4.)