|
|
A339774
|
|
a(n) is the least k such that 3^k == A047471(n) (mod 2^A047471(n)).
|
|
1
|
|
|
0, 1, 2, 39, 23988, 2685, 1079830, 3, 1798749736, 7936950713, 314244766442, 895397198495, 65283613526364, 203550894972341, 27025091041430142, 54487836217255419, 2756442714229679952, 34856858877609547377, 2262552012902592868562, 4616799241038411627031, 4, 116433218705414728492013
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,3
|
|
COMMENTS
|
For n >= 3, 3^x == y (mod 2^n) has solutions x if and only if y is in A047471.
|
|
LINKS
|
|
|
FORMULA
|
a((3^k - (-1)^k)/4 + 1) = k.
|
|
EXAMPLE
|
a(4) = 39 because A047471(4) = 11 and 3^39 == 11 (mod 2^11).
|
|
MAPLE
|
f:= proc(n) local k, v;
v:= subs(msolve(3^k=n, 2^n), k);
subs(op(indets(v))=0, v)
end proc:
seq(seq(f(8*i+j), j=[1, 3]), i=0..10);
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|