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A336760
a(0) = 0; for n > 0, a(n) = a(n-1) - tau(n) if nonnegative and not already in the sequence, otherwise a(n) = a(n-1) + tau(n), where tau(n) is the number of divisors of n.
8
0, 1, 3, 5, 2, 4, 8, 6, 10, 7, 11, 9, 15, 13, 17, 21, 16, 14, 20, 18, 12, 16, 20, 22, 30, 27, 23, 19, 25, 27, 35, 33, 39, 43, 47, 51, 42, 40, 36, 32, 24, 26, 34, 36, 42, 48, 44, 46, 56, 53, 59, 55, 49, 51, 59, 63, 71, 67, 71, 69, 57, 59, 63, 69, 62, 58, 50, 52, 58, 54, 62, 60, 72, 70, 66, 72
OFFSET
0,3
COMMENTS
This sequences uses the same rules as Recamán's sequence A005132 except that, instead of adding or subtracting n each term, the number of divisors of n is used. See A000005.
For the first 10 million terms the smallest value not appearing is 28. The data indicate that a(n)/n approaches 1 as n goes to infinity. As tau(n) <= 2*sqrt(n) (see A046522), it implies that 28 and other small unvisited values will never be visited.
In the same range the maximum value is a(9998226) = 10987569, and 2202001 terms repeat a previously visited value, the first time this occurs is a(21) = a(16) = 16. The longest run of consecutive increasing terms is 30, starting at a(1115610) = 1217112, while the longest run of consecutive decreasing terms is 534, starting at a(9960335) = 10946233.
EXAMPLE
a(2) = 3. As 2 has two divisors, a(2) = a(1) + 2 = 1 + 2 = 3.
a(4) = 2. As 4 has three divisors, and as 2 has not been previously visited and is nonnegative, a(4) = a(3) - 3 = 5 - 3 = 2.
CROSSREFS
KEYWORD
nonn
AUTHOR
Scott R. Shannon, Aug 03 2020
STATUS
approved