OFFSET
1,4
LINKS
Lars Blomberg, Table of n, a(n) for n = 1..500
FORMULA
It seems that a(n) = A018811(n+1) / 2 for n > 3. - Andrei Zabolotskii, Jun 06 2026
CROSSREFS
KEYWORD
nonn,changed
AUTHOR
Lars Blomberg, Jul 25 2020
STATUS
approved
