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A335835
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Sort the run lengths in binary expansion of n in desccending order (with multiplicities).
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4
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0, 1, 2, 3, 6, 5, 6, 7, 14, 13, 10, 13, 12, 13, 14, 15, 30, 29, 26, 25, 26, 21, 26, 29, 28, 25, 26, 25, 28, 29, 30, 31, 62, 61, 58, 57, 50, 53, 50, 57, 58, 53, 42, 53, 50, 53, 58, 61, 60, 57, 50, 51, 50, 53, 50, 57, 56, 57, 58, 57, 60, 61, 62, 63, 126, 125
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OFFSET
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0,3
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COMMENTS
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This sequence preserves the number of runs (A005811) and the length (A070939) of the binary representation of a number.
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LINKS
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FORMULA
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a(a(n)) = a(n).
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EXAMPLE
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For n = 72:
- the binary representation of 72 is "1001000",
- the corresponding run lengths are: 1, 2, 1, 3,
- in descending order: 3, 2, 1, 1,
- so the binary representation of a(72) is "1110010",
- and a(72) = 114.
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PROG
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(PARI) torl(n) = { my (rr=[]); while (n, my (r=valuation(n+(n%2), 2)); rr = concat(r, rr); n\=2^r); rr }
fromrl(rr) = { my (v=0); for (k=1, #rr, v = (v+(k%2))*2^rr[k]-(k%2)); v }
a(n) = { fromrl(vecsort(torl(n), , 4)) }
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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