login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A335297
Integers k such that for all m>k, d(m)/m < d(k)/k where d(j) = Min_{p & q odd primes, 2*j = p+q, p <= q} (q-p)/2.
1
22, 46, 58, 146, 344, 362, 526, 1114, 1781, 2476, 3097, 3551, 5131, 5728, 8504, 10342, 10907, 10994, 13321, 13924, 13984, 18526, 24776, 26197, 30728, 40072, 44656, 44860, 68707, 70757, 71684, 76861, 78461, 89812, 125903, 181267, 191771, 227566, 256849, 278566, 371428, 379969
OFFSET
1,1
COMMENTS
This sequence is related to a stronger form of Goldbach conjecture, and the formulation of the conjecture is the following.
Conjecture: Let
Gs(m) be the number of unordered pairs of odd prime numbers p and q such that an even number 2m can be written as the sum of p and q, or, Gs(m) = # { (p,q) | 2m = p+q }, where p <= q;
d be half of the minimum difference between q and p, or, d = min((q-p)/2);
r be the ratio of d/m, or, r = d/m; and
a(n) be the n-th number such that r = d/m is decreasing, or, r(m) < r(a(n+1)), if a(n) <= m < a(n+1), where n = 0, 1, 2, 3, .... and a(0)=3.
The conjecture states that
Gs(m) >= 1 if r(m) >= r(a(n+1)) where a(n) <= m < a(n+1).
EXAMPLE
For even numbers 2m >= 6 (6 is the smallest even number that can be written as the sum of two odd primes), the list of m is:
m = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, ...}.
The corresponding values of d and r, according to the definition, are given in the following two lists:
d = {0, 1, 0, 1, 0, 3, 2, 3, 0, 1, 0, 3, 2, 3, 0, 1, 0, 3, 2, 9, 0, 5, 6, 3, 4, 9, 0, 1, 0, 9, 4, 3, 6, 5, 0, 9, 2, 3, 0, 1, 0, 3, 2, 15, ...}, and
r = {0, 1/4, 0, 1/6, 0, 3/8, 2/9, 3/10, 0, 1/12, 0, 3/14, 2/15, 3/16, 0, 1/18, 0, 3/20, 2/21, 9/22, 0, 5/24, 6/25, 3/26, 4/27, 9/28, 0, 1/30, 0, 9/32, 4/33, 3/34, 6/35, 5/36, 0, 9/38, 2/39, 3/40, 0, 1/42, 0, 3/44, 2/45, 15/46, ...}.
In the list of r, the first number that is bigger than all the preceding numbers is r = 9/22, which is corresponding to the number m = 22 in the list of m. Therefore, the first number of the sequence is 22, or a(1) = 22.
In the range of (9/22, 15/46], r= 15/46 is the biggest number. Since r = 15/46 corresponds to m = 46, the 2nd number of the sequence is 46, or a(2) = 46.
The first number in the list of m, 3, is defined as the zeroth term of the sequence, or a(0) = 3.
PROG
(PARI) mindiff(n) = {forstep(k=n/2, 1, -1, if (isprime(k) && isprime(n-k), return(n-2*k)); ); }
upto(n) = res=List(); r=0; forstep(i=n, 1, -1, c= mindiff(2*i) / (2*i); if(c>r, r=c; listput(res, i))); Vecrev(Vec(res)) \\ David A. Corneth, Jun 02 2020
CROSSREFS
Sequence in context: A106838 A190614 A281187 * A158862 A161666 A132763
KEYWORD
nonn
AUTHOR
Ya-Ping Lu, May 30 2020
STATUS
approved