OFFSET
0,8
COMMENTS
A square-(sub)word consists of two nonempty identical adjacent subwords.
This sequence is a binary variant of A088950.
Square-subwords are counted with multiplicity.
A binary word of length 4 contains necessarily a square-subword, hence a(n) tends to infinity as n tends to infinity (a number whose binary representation has >= 4*k digits has >= k square-subwords).
LINKS
Rémy Sigrist, Table of n, a(n) for n = 0..16384
Eric Weisstein's World of Mathematics, Squarefree Word
FORMULA
a(2^k) = a(2^k-1) = A002620(k) for any k >= 0.
EXAMPLE
For n = 43:
- the binary representation of 43 is "101011",
- we have the following square-subwords: "1010", "0101", "11",
- hence a(43) = 3.
PROG
(PARI) a(n, base=2) = { my (b=digits(n, base), v); for (w=1, #b\2, for (i=1, #b-2*w+1, if (b[i..i+w-1]==b[i+w..i+2*w-1], v++))); return (v) }
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Rémy Sigrist, Mar 08 2020
STATUS
approved