OFFSET
1,1
COMMENTS
The sequence is infinite as one can always multiply a(4n+1) by 10 and do the same with the next three terms. It is conjectured that at least two of those three terms must be equal.
LINKS
Éric Angelini, post to Math-Fun
EXAMPLE
For n = 0, we have a(4n+1) = a(1) = 15 and 15 is the sum 5 + 5 + 5, those last three terms being a(2), a(3), a(4) and substrings of a(1);
For n = 3, we have a(4n+1) = a(13) = 182 and 182 is the sum 18 + 82 + 82, those last three terms being a(14), a(15), a(16) and substrings of a(13).
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Eric Angelini and Tom Duff, Feb 26 2020
STATUS
approved