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 A330003 Beatty sequence for (x+1)^2, where 1/x + 1/(x+1)^2 = 1. 3
 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100, 106, 111, 116, 121, 126, 131, 136, 141, 146, 151, 156, 161, 166, 171, 176, 181, 186, 191, 196, 201, 207, 212, 217, 222, 227, 232, 237, 242, 247, 252, 257, 262, 267, 272, 277, 282 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS Let x be the solution of 1/x + 1/(x+1)^2 = 1. Then (floor(n x) and (floor(n (x+1)^2))) are a pair of Beatty sequences; i.e., every positive integer is in exactly one of the sequences. See the Guide to related sequences at A329825. LINKS Eric Weisstein's World of Mathematics, Beatty Sequence. FORMULA a(n) = floor(n x), where x = 1.24697960371... is the constant in A255249. MATHEMATICA r = x /. FindRoot[1/x + 1/(x+1)^2 == 1, {x, 2, 10}, WorkingPrecision -> 120] RealDigits[r][] (* A255249 *) Table[Floor[n*r]], {n, 1, 250}]       (* A330002 *) Table[Floor[n*(1+r)^2], {n, 1, 250}]  (* A330003 *) CROSSREFS Cf. A329825, A255249, A330002 (complement). Sequence in context: A172336 A140233 A172328 * A061821 A085128 A313734 Adjacent sequences:  A330000 A330001 A330002 * A330004 A330005 A330006 KEYWORD nonn,easy AUTHOR Clark Kimberling, Jan 04 2020 STATUS approved

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Last modified May 7 00:04 EDT 2021. Contains 343609 sequences. (Running on oeis4.)