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%I #8 Oct 28 2019 20:01:50
%S 1,10,11,2,3,4,5,6,7,8,9,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,
%T 27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,
%U 50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67
%N Lexicographically earliest sequence of distinct positive numbers such that for any n > 0, the first nonzero digit of a(n+1)/a(n) is "1".
%C In other words, for any n > 0, we have an integer k such that floor(10^k * a(n+1)/a(n)) = 1.
%H Rémy Sigrist, <a href="/A328752/a328752.gp.txt">PARI program for A328752</a>
%F a(n) = n for n > 11.
%e The first terms, alongside a(n+1)/a(n), are:
%e n a(n) a(n+1)/a(n)
%e -- ---- -----------
%e 1 1 10
%e 2 10 1.1
%e 3 11 0.18181818...
%e 4 2 1.5
%e 5 3 1.33333333...
%e 6 4 1.25
%e 7 5 1.2
%e 8 6 1.16666666...
%e 9 7 1.14285714...
%e 10 8 1.125
%e 11 9 1.33333333...
%e 12 12 1.08333333...
%o (PARI) See Links section.
%Y See A328753, A328754, A328755, A328756, A328757, A328758, A328759 and A328760 for the variants where a(n+1)/a(n) starts with "2", "3", "4", "5", "6", "7", "8" and "9", respectively.
%K nonn,base
%O 1,2
%A _Rémy Sigrist_, Oct 27 2019
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