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A324010
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The sum of squares of the number of common points in all pairs of lattice paths from (0,0) to (x,y), for x >= 0, y >= 0 (the unnormalized second moment). The table is read by antidiagonals.
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1
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1, 4, 4, 9, 26, 9, 16, 92, 92, 16, 25, 240, 474, 240, 25, 36, 520, 1704, 1704, 520, 36, 49, 994, 4879, 8084, 4879, 994, 49, 64, 1736, 11928, 29560, 29560, 11928, 1736, 64, 81, 2832, 25956, 89928, 134450, 89928, 25956, 2832, 81, 100, 4380, 51648, 238440, 498140, 498140, 238440, 51648, 4380, 100
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OFFSET
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0,2
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LINKS
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FORMULA
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A(x,y) = (x+y+1) * binomial(x+y+2,x+1) * binomial(x+y,x) - binomial(2*x+2*y+2,2*x+1)/2.
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EXAMPLE
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There are two lattice paths from (0,0) to (x,y)=(1,1): P1=(0,0),(1,0),(1,1) and P2=(0,0),(0,1),(1,1), and hence 4 pairs of lattice paths: (P1,P1),(P1,P2),(P2,P1),(P2,P2). The number of common points is 3,2,2,3, respectively, and the sum of the squares of these numbers is 9+4+4+9 = 26 = a(1,1).
Table begins
1 4 9 16 25 ...
4 26 92 240 520 ...
9 92 474 1704 4879 ...
16 240 1704 8084 29560 ...
25 520 4879 29560 134450 ...
...
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MATHEMATICA
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Table[(# + y + 1) Binomial[# + y + 2, # + 1] Binomial[# + y, #] - Binomial[2 # + 2 y + 2, 2 # + 1]/2 &[x - y], {x, 0, 9}, {y, 0, x}] // Flatten (* Michael De Vlieger, Apr 15 2019 *)
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PROG
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(PARI) a(x, y) = (x+y+1)*binomial(x+y+2, x+1)*binomial(x+y, x)-binomial(2*x+2*y+2, 2*x+1)/2;
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CROSSREFS
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See A306687 for the lower triangular half of the same data, read by rows.
See A091044 for the unnormalized first moment (the sum of the number of common points without squaring).
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KEYWORD
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AUTHOR
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STATUS
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approved
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