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A322086 One of the two successive approximations up to 13^n for 13-adic integer sqrt(3). Here the 9 (mod 13) case (except for n = 0). 7
0, 9, 61, 1075, 9863, 9863, 3722793, 56817692, 245063243, 2692255406, 23901254152, 1540344664491, 12293307028713, 198677988008561, 804428201193067, 24428686515388801, 75614579529479558, 741031188712659399, 26692278946856673198, 813880127610558425101, 11047322160238681199840 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
For n > 0, a(n) is the unique solution to x^2 == 3 (mod 13^n) in the range [0, 13^n - 1] and congruent to 9 modulo 13.
A322085 is the approximation (congruent to 4 mod 13) of another square root of 3 over the 13-adic field.
LINKS
Wikipedia, p-adic number
FORMULA
For n > 0, a(n) = 13^n - A322085(n).
a(n) = Sum_{i=0..n-1} A322088(i)*13^i.
a(n) = A286840(n)*A322090(n) mod 13^n = A286841(n)*A322089(n) mod 13^n.
EXAMPLE
9^2 = 81 = 6*13 + 3.
61^2 = 3721 = 22*13^2 + 3.
1075^2 = 1155625 = 526*13^3 + 3.
MAPLE
S:= map(t -> op([1, 3], t), [padic:-evalp(RootOf(x^2-3, x), 13, 30)]):
S9:= op(select(t -> t[1]=9, S)):
seq(add(S9[i]*13^(i-1), i=1..n-1), n=1..31); # Robert Israel, Jun 13 2019
PROG
(PARI) a(n) = truncate(-sqrt(3+O(13^n)))
CROSSREFS
Sequence in context: A361280 A025014 A246567 * A075139 A264376 A328955
KEYWORD
nonn
AUTHOR
Jianing Song, Nov 26 2018
STATUS
approved

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Last modified March 29 11:14 EDT 2024. Contains 371278 sequences. (Running on oeis4.)