OFFSET
0,2
FORMULA
a(n) = numerator(binomial(2*n, n)/4^n) * (2*n+1)^2. - G. C. Greubel, Dec 07 2018
From Peter Bala, Apr 27 2024: (Start)
[x^n] 3F2([1/2, 1, 1], [3/2, 3/2], x) = 1/(2*n + 1) * Integral_{x = 0..1} (1 - x^2)^n dx = 1/(2*n + 1) * Sum_{k = 0..n} (-1)^k * binomial(n, k)/(2*k + 1).
a(n) = denominator of 2^(2*n+1)/ ((n + 1)*(2*n + 1)*binomial(2*n+2, n+1)). (End)
MAPLE
a:=n->(2*n+1)^2*binomial(2*n, n)/4^n: seq(numer(a(n)), n=0..25); # Muniru A Asiru, Dec 08 2018
MATHEMATICA
Denominator[CoefficientList[Series[HypergeometricPFQ[{1/2, 1, 1}, {3/2, 3/2}, c], {c, 0, 20}], c]]
Table[(2*n+1)^2*Numerator[Binomial[2*n, n]/4^n], {n, 0, 30}] (* G. C. Greubel, Dec 07 2018 *)
PROG
(PARI) vector(30, n, n--; numerator(binomial(2*n, n)/4^n)*(2*n+1)^2) \\ G. C. Greubel, Dec 07 2018
(Magma) [Numerator(Binomial(2*n, n)/4^n)*(2*n+1)^2: n in [0..30]]; // G. C. Greubel, Dec 07 2018
(Sage) [numerator(binomial(2*n, n)/4^n)*(2*n+1)^2 for n in range(30)] # G. C. Greubel, Dec 07 2018
(GAP) List([0..30], n -> NumeratorRat(Binomial(2*n, n)/4^n)*(2*n+1)^2); # G. C. Greubel, Dec 07 2018
CROSSREFS
KEYWORD
nonn,frac
AUTHOR
Eugene d'Eon, Nov 01 2018
STATUS
approved