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A321028
a(n) = 6 + round(n^3) - (minimal number of squares in a dissection of an (n) X (n+1) oblong into squares).
1
5, 4, 3, 3, 3, 3, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 1, 2, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, 0, 0, -1, -1, 0, 0, 0, 0, 0, 0, -1, 0, -1, 0, -1, 0, -1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, -1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
OFFSET
1,1
COMMENTS
After a(18) = 2, all terms through a(387) are in (-1,0,1). The first known term outside of this range is a(969) >= 2.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..387 (calculated from the b-file at A279317)
Ed Pegg Jr, Oblongs into minimal squares, StackExchange, Dec 13 2016.
FORMULA
a(n) = 6 + A105209(n) - A279317(n).
CROSSREFS
Sequence in context: A276052 A374420 A348340 * A351169 A395136 A396022
KEYWORD
hard,sign
AUTHOR
Ed Pegg Jr, Oct 26 2018
STATUS
approved