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A309782
The sequence S is always extended with the smallest integer not yet present that begins with the sum of the two digits enclosing the last comma; a(1) = 1 is separated from a(2) = 2 by the first comma.
1
1, 2, 3, 5, 8, 13, 9, 12, 10, 30, 31, 32, 4, 6, 100, 7, 70, 14, 11, 50, 60, 61, 62, 71, 90, 101, 15, 20, 72, 73, 91, 120, 21, 22, 33, 51, 80, 92, 93, 110, 40, 41, 42, 52, 74, 94, 130, 53, 54, 81, 121, 23, 34, 63, 102, 43, 64, 95, 131, 65, 75, 122, 66, 82, 140, 35, 36, 83, 141, 44, 55, 96, 142, 76, 97, 150, 84, 85, 123, 67
OFFSET
1,2
COMMENTS
This sequence is conjectured to be a permutation of the integers > 0.
LINKS
EXAMPLE
The sequence S begins with 1,2,3,5,8,13,9,12,10,30,31,32,4,...
The 1st comma separates the digits 1 and 2; sum is 3; a(3) = 3;
the 2nd comma separates the digits 2 and 3; sum is 5; a(4) = 5;
the 3rd comma separates the digits 3 and 5; sum is 8; a(5) = 8;
the 4th comma separates the digits 5 and 8; sum is 13; a(6) = 13;
the 5th comma separates the digits 8 and 1; sum is 9; a(7) = 9;
the 6th comma separates the digits 3 and 9; sum is 12; a(8) = 12;
the 7th comma separates the digits 9 and 1; sum is 10; a(9) = 10;
the 8th comma separates the digits 2 and 1; sum is 3; a(10) = 30 (as 3 is already in S);
the 9th comma separates the digits 0 and 3; sum is 3; a(11) = 31 (as 3 and 30 are already in S);
the 10th comma separates the digits 0 and 3; sum is 3; a(12) = 32 (3, 30 and 31 are already in S);
the 11th comma separates the digits 1 and 3; sum is 4 a(13) = 4;
etc.
CROSSREFS
Sequence in context: A254032 A214365 A104701 * A300999 A074867 A131297
KEYWORD
nonn,base
AUTHOR
STATUS
approved