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A302928 Maximum number of 4's possible in an infinite Minesweeper grid with n mines. 4
0, 0, 0, 2, 2, 4, 6, 6, 7, 8, 10, 12, 12, 13, 14, 16, 18, 18, 19, 21, 22, 24, 24, 26, 28, 30, 30, 31, 33, 34, 36, 36 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,4
COMMENTS
Question: what is the maximum value possible for (a(n) - n)? The current record is 5, which occurs at n=31.
There is no maximum. We can take k copies of the 17-mine configuration and place them sufficiently far apart to get 18k fours. So a(17k) - 17k >= 18k - 17k = k can get arbitrarily large. A possibly more interesting question is to ask about the maximum ratio a(n)/n. - Yevhenii Diomidov, Jan 19 2022
LINKS
Dmitry Kamenetsky, The first 32 solutions
Wikipedia, Minesweeper.
CROSSREFS
Sequence in context: A062722 A160731 A323647 * A098214 A178883 A109832
KEYWORD
nonn,more
AUTHOR
Dmitry Kamenetsky, Apr 16 2018
STATUS
approved

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Last modified June 16 08:45 EDT 2024. Contains 373424 sequences. (Running on oeis4.)