login
A301936
Decimal expansion of the molar volume of a perfect gas in standard conditions in cubic meters per mole.
0
OFFSET
1,1
COMMENTS
For a perfect gas we know Vm = RT/p. Where p is the pressure, Vm is the molar volume, T is the temperature and R is the molar gas constant. We will use the value of R according to NIST.
In standard conditions T = 298.15 K, p = 100000 Pa therefore:
Vm = A070064 J mol^-1 K^-1 * 298.15 K / 100000 Pa = 0.024789561 (14) m^3 mol^-1.
The number (14) denotes the current uncertainty of the value.
FORMULA
Vm = A070064 * 0.0029815.
Vm = 0.024789561 (14) m^3 mol^-1.
CROSSREFS
Cf. A070064.
Sequence in context: A182842 A009282 A141745 * A372431 A285535 A342777
KEYWORD
nonn,cons,more
AUTHOR
Natan Arie Consigli, Mar 28 2018
STATUS
approved