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A300284
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Decimal expansion of the probability that a bullet, shot randomly at a cube that is thrown into the air, will pass through the opposite side.
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0
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1, 9, 9, 8, 2, 4, 8, 9, 5, 6, 9, 8, 3, 8, 7, 3, 8, 3, 0, 4, 1, 5, 9, 9, 2, 5, 1, 1, 9, 3, 0, 6, 8, 7, 2, 8, 1, 1, 8, 2, 3, 9, 7, 6, 9, 6, 9, 0, 3, 0, 3, 8, 7, 1, 5, 8, 3, 1, 2, 6, 8, 9, 5, 4, 5, 4, 9, 6, 1, 7, 9, 6, 4, 4, 1, 6, 8, 4, 5, 7, 7, 6, 2, 3, 8, 2, 5
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OFFSET
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0,2
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COMMENTS
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The solution to the problem proposed and solved by Enoch Beery Seitz in 1882: "A cube is thrown into the air and a random shot fired through it; find the chance that the shot passes through the opposite side."
The corresponding probability for the 2D case is 1/2 - log(2)/Pi = 0.279364...
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REFERENCES
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Stanley Rabinowitz, Problems and Solutions from the Mathematical Visitor 1877-1896, MathPro Press, 1991, page 26.
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LINKS
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Enoch Beery Seitz, Problem 201, The Mathematical Visitor, Vol. 2, No. 1 (1882), p. 21.
Benjamin Franklin Finkel, Biography: E. B. Seitz, The American Mathematical Monthly, Vol. 1, No. 1 (1894), pp. 3-6.
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FORMULA
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Equals ((4*sqrt(2)*arctan(1/sqrt(2)) + log(4/3) - Pi)/Pi.
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EXAMPLE
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0.1998248956983873830415992511930687281182397696903038715831268954549617964416...
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MATHEMATICA
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RealDigits[(4*Sqrt[2]*ArcTan[1/Sqrt[2]]+Log[4/3]-Pi)/Pi, 10, 100][[1]]
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CROSSREFS
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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