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A294904 Number of divisors of n that are in A175526. 7
0, 0, 0, 1, 0, 1, 0, 2, 1, 1, 0, 3, 0, 1, 1, 3, 0, 3, 0, 3, 1, 1, 0, 5, 0, 1, 2, 3, 0, 4, 0, 4, 1, 1, 1, 6, 0, 1, 1, 5, 0, 4, 0, 3, 3, 1, 0, 7, 1, 2, 1, 3, 0, 5, 1, 5, 1, 1, 0, 8, 0, 1, 3, 5, 1, 4, 0, 3, 1, 4, 0, 9, 0, 1, 2, 3, 1, 4, 0, 7, 3, 1, 0, 8, 1, 1, 1, 5, 0, 8, 1, 3, 1, 1, 0, 9, 0, 3, 3, 5, 0, 4, 0, 5, 4, 1, 0, 9, 0, 4, 0, 7, 0, 4, 1, 3, 3, 1, 0, 12 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,8
COMMENTS
Number of terms of A175526 that divide n.
LINKS
FORMULA
a(n) = Sum_{d|n} (1-A294905(d)).
a(n) = 1 + (A294902(n)-A294905(n)).
a(n) + A294903(n) = A000005(n).
MATHEMATICA
q[n_] := DivisorSum[n, DigitCount[#, 2, 1] &] > 2 * DigitCount[n, 2, 1]; a[n_] := DivisorSum[n, 1 &, q[#] &]; Array[a, 100] (* Amiram Eldar, Jul 20 2023 *)
PROG
(PARI)
A292257(n) = sumdiv(n, d, (d<n)*hammingweight(d));
A294905(n) = (A292257(n) <= hammingweight(n));
A294904(n) = sumdiv(n, d, (0==A294905(d)));
CROSSREFS
Cf. also A294894.
Sequence in context: A114206 A073202 A337345 * A055212 A360661 A028422
KEYWORD
nonn,base
AUTHOR
Antti Karttunen, Nov 10 2017
STATUS
approved

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Last modified April 19 03:30 EDT 2024. Contains 371782 sequences. (Running on oeis4.)