|
|
A292202
|
|
The n-th iteration of A062028 starting with n.
|
|
2
|
|
|
2, 8, 15, 28, 25, 33, 59, 77, 90, 79, 109, 111, 134, 137, 129, 148, 184, 189, 218, 197, 204, 226, 250, 231, 284, 284, 297, 313, 325, 309, 341, 398, 354, 418, 418, 414, 488, 440, 438, 478, 529, 465, 545, 554, 531, 628, 658, 561, 620, 677, 624, 697, 697, 657, 785, 818, 735, 865, 835, 762, 851, 851
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
a(n) == n*2^n (mod 9). This has a period of 18. - Robert Israel, Sep 11 2017
|
|
LINKS
|
|
|
EXAMPLE
|
n=5: 5+5=10, 10+1+0=11, 11+1+1=13, 13+1+3=17, 17+1+7=25. After 5 iterations you get 25, so a(5)=25.
|
|
MAPLE
|
A062028:= proc(t) option remember; t + convert(convert(t, base, 10), `+`):end proc:
|
|
MATHEMATICA
|
Table[Nest[# + Total@ IntegerDigits@ # &, n, n], {n, 62}] (* Michael De Vlieger, Sep 11 2017 *)
|
|
PROG
|
(PARI) a(n) = my(x=n); for (k=1, n, x += sumdigits(x)); x; \\ Michel Marcus, Sep 12 2017
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|