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Length of runs of equal terms in A007944.
1

%I #12 Jan 10 2018 03:37:45

%S 1,1,1,1,1,1,1,2,1,1,2,3,1,2,2,1,1,1,1,2,1,1,1,2,1,1,2,3,1,2,3,2,2,1,

%T 2,5,2,2,1,3,2,1,1,1,5,4,2,3,2,3,2,2,1,5,4,1,6,3,4,2,4,2,2,1,2,3,2,3,

%U 3,5,1,1,3,6,1,8,1,6,1,9,2,5,10,2,3,6,1,3

%N Length of runs of equal terms in A007944.

%H David A. Corneth, <a href="/A290267/b290267.txt">Table of n, a(n) for n = 1..13690</a>

%e The first 7 terms in A007944 are all distinct; they are 6, 10, 14, 18, 26, 30, 38. So a(1) = a(2) = ... = a(7) = 1. The next three terms in A007944 are 42, 42 and 54, so a run of 2 equal terms giving a(8) = 2.

%Y Cf. A007944.

%K nonn

%O 1,8

%A _David A. Corneth_, Jul 25 2017