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A289712
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Smallest integer such that the sum of its n smallest divisors is a square.
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2
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1, 3, 15, 22, 12, 36, 24, 66, 126, 420, 90, 364, 270, 264, 240, 210, 672, 780, 864, 1050, 672, 720, 924, 1092, 1344, 3240, 3312, 1260, 3600, 1200, 8910, 1080, 27104, 5940, 1680, 8568, 8910, 14280, 6384, 5670, 5544, 9600, 43092, 42900, 5280, 3360, 9504, 8580, 21600, 54288
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OFFSET
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1,2
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COMMENTS
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The first corresponding squares are 1, 4, 9, 36, 16, 25, 36, 144, 81, ...
The first squares in the sequence are 1, 36, 3600, ...
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LINKS
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EXAMPLE
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a(4)=22 because the sum of the first 4 divisors of 22, i.e., 1 + 2 + 11 + 22 = 36, is a square, and 22 is the smallest integer with this property.
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MAPLE
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N:= 5*10^5: # to get terms before the first term > N
for k from 1 to N do
d:= sort(convert(numtheory:-divisors(k), list));
s:= ListTools:-PartialSums(d);
for m from 1 to nops(d) do
if not assigned(A[m]) and issqr(s[m]) then A[m]:= k fi
od
od:
iA:= map(op, {indices(A)}):
seq(A[i], i=1..min({$1..max(iA)+1} minus iA)-1); # Robert Israel, Oct 01 2017
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MATHEMATICA
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Table[k=1; While[Nand[Length@#>=n, IntegerQ[Sqrt[Total@Take[PadRight[#, n], n]]]]&@Divisors@k, k++]; k, {n, 1, 50}] (* Program from Michael De Vlieger adapted for this sequence. See A289776. *)
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PROG
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(PARI) isok(k, n) = {my(v = divisors(k)); if (#v < n, return(0)); issquare(sum(j=1, n, v[j])); }
a(n) = {my(k = 1); while(!isok(k, n), k++); k; } \\ Michel Marcus, Sep 04 2017
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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