%I #4 Apr 25 2017 11:45:54
%S 2,3,4,6,8,10,12,13,14,16,18,19,20,22,24,25,26,28,30,31,32,34,36,38,
%T 40,41,42,44,46,47,48,50,52,54,56,57,58,60,62,63,64,66,68,70,72,73,74,
%U 76,78,79,80,82,84,86,88,89,90,92,94,95,96,98,100,101,102
%N Positions of 0 in A285301, complement of A086398.
%C Conjecture: -2 < n*r - a(n) < 2 for n>=1, where r = 1 + sqrt(1/3).
%H Clark Kimberling, <a href="/A285302/b285302.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A284301 = 100010..., in which the positions of 0 are 2,3,4,6,8,...
%t s = Nest[Flatten[# /. {0 -> {1, 0}, 1 -> {1, 0, 0, 0}}] &, {0}, 10]; (* A285301 *)
%t u = Flatten[Position[s, 0]]; (* A285302 *)
%t v = Flatten[Position[s, 1]]; (* A086398 *)
%Y Cf. A284301, A086398.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, Apr 25 2017