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Positions of 0 in A285080; complement of A285082.
3

%I #4 Apr 20 2017 09:23:18

%S 1,5,7,8,11,15,16,19,23,24,27,30,34,36,37,40,43,47,48,52,54,55,58,62,

%T 63,66,69,73,75,76,79,83,84,87,91,92,95,98,102,103,107,109,110,113,

%U 117,118,121,124,128,130,131,134,138,139,142,146,147,150,153,157

%N Positions of 0 in A285080; complement of A285082.

%C Conjecture: 0 < n*r - a(n) < r for n>=1, where r = (3+sqrt(5))/2.

%H Clark Kimberling, <a href="/A285081/b285081.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A285080 = 01110..., in which 0 is in positions 1,5,7,8,11,...

%t s = Nest[Flatten[# /. {0 -> {1, 0}, 1 -> {0, 1, 1}}] &, {0}, 14]; (* A285080 *)

%t Flatten[Position[s, 0]]; (* A285081 *)

%t Flatten[Position[s, 1]]; (* A285082 *)

%Y Cf. A285080, A285082, A285083, A285084.

%K nonn,easy

%O 1,2

%A _Clark Kimberling_, Apr 19 2017